What is the derivative of y=(4x-1)^2 ?

The derivative of y=(4x-1)^2 is 8(4x-1)

What is the first derivative of y=(4x-1)^2 ?

The first derivative of y=(4x-1)^2 is 8(4x-1)

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derivative of

y = (4 x - 1)^{2}

8 (4 x - 1)

Solution steps

\frac{d}{d x} ((4 x - 1)^{2})

Apply the chain rule:

2 (4 x - 1) \frac{d}{d x} (4 x - 1)

= 2 (4 x - 1) \frac{d}{d x} (4 x - 1)

\frac{d}{d x} (4 x - 1) = 4

= 2 (4 x - 1) \cdot 4

Simplify

= 8 (4 x - 1)

\frac{d}{d x} ((3 x + 4) (- 3 + 2 x))

\int (3 x + 8)^{\frac{2}{3}} d x

\frac{d}{d x} (\frac{2}{( x - 1 ) ^{2}})

\int \frac{1 - sin ( x )}{1 + sin ( x )} d x

\frac{d r}{d θ} + r tan (θ) = 5 tan (θ)

What is the derivative of y=(4x-1)^2 ?
The derivative of y=(4x-1)^2 is 8(4x-1)
What is the first derivative of y=(4x-1)^2 ?
The first derivative of y=(4x-1)^2 is 8(4x-1)