What is area 1/(3(1+x^2)), 1/6 x^2 ?

The answer to area 1/(3(1+x^2)), 1/6 x^2 is pi/6-1/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area 1/(3(1+x^2)), 1/6 x^2

area

\frac{1}{3 ( 1 + x ^{2} )}, \frac{1}{6} x^{2}

\frac{π}{6} - \frac{1}{9}

Decimal Notation

0.41248 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{1} \frac{1}{3 ( 1 + x ^{2} )} - \frac{1}{6} x^{2} d x

Solve

\int_{- 1}^{1} \frac{1}{3 ( 1 + x ^{2} )} - \frac{1}{6} x^{2} d x : \frac{π}{6} - \frac{1}{9}

The area is:

= \frac{π}{6} - \frac{1}{9}

x y^{^{''}} + 2 y^{^{'}} = 4 x^{2}

\frac{d}{d x} (lo g_{4} (x^{2} + 3))

\int \frac{1}{x ( x + 1 )} d x

x^{3} - 3 x^{2} + 2 x - 2, at x = 2

\frac{d}{d x} (2 - e^{x})

What is area 1/(3(1+x^2)), 1/6 x^2 ?
The answer to area 1/(3(1+x^2)), 1/6 x^2 is pi/6-1/9