What is the tangent of x^3-3x^2+2x-2,\at x=2 ?

The tangent of x^3-3x^2+2x-2,\at x=2 is y=2x-6

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tangent of x^3-3x^2+2x-2,\at x=2

tangent of

x^{3} - 3 x^{2} + 2 x - 2, at x = 2

y = 2 x - 6

Solution steps

Find the tangent point:

(2, - 2)

Find the slope of

y = x^{3} - 3 x^{2} + 2 x - 2 : \frac{d y}{d x} = 3 x^{2} - 6 x + 2

Compute the slope of

y = x^{3} - 3 x^{2} + 2 x - 2

x = 2 : m = 2

Find the line with slope m=

2

and passing through

(2, - 2) : y = 2 x - 6

y = 2 x - 6

\frac{d}{d x} (2 - e^{x})

\frac{d y}{d x} - \frac{2}{x} y = x

\int (e^{3.1})^{2} d x

\frac{d}{d x} (cos (2 sin (x)))

x \to 2 lim (x^{2} + 2 x - 1)

What is the tangent of x^3-3x^2+2x-2,\at x=2 ?
The tangent of x^3-3x^2+2x-2,\at x=2 is y=2x-6