What is the derivative of f(x)=8x^2-x^3 ?

The derivative of f(x)=8x^2-x^3 is 16x-3x^2

What is the first derivative of f(x)=8x^2-x^3 ?

The first derivative of f(x)=8x^2-x^3 is 16x-3x^2

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derivative of

f (x) = 8 x^{2} - x^{3}

16 x - 3 x^{2}

Solution steps

\frac{d}{d x} (8 x^{2} - x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x^{2}) - \frac{d}{d x} (x^{3})

\frac{d}{d x} (8 x^{2}) = 16 x

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 16 x - 3 x^{2}

\int x^{3} x^{2} + 17 d x

\frac{d v}{d t} = k \cdot (275 - v), v (0) = 0

cos^{2} (x) + sin^{2} (x)

y = ln (x^{2} - 9 x + 1), (9, 0)

\int 5 sin (t) d t

What is the derivative of f(x)=8x^2-x^3 ?
The derivative of f(x)=8x^2-x^3 is 16x-3x^2
What is the first derivative of f(x)=8x^2-x^3 ?
The first derivative of f(x)=8x^2-x^3 is 16x-3x^2