What is the integral of 5sin(t) ?

The integral of 5sin(t) is -5cos(t)+C

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integral of 5sin(t)

\int 5 sin (t) d t

- 5 cos (t) + C

Solution steps

\int 5 sin (t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int sin (t) d t

Use the common integral:

\int sin (t) d t = - cos (t)

= 5 (- cos (t))

Simplify

= - 5 cos (t)

Add a constant to the solution

= - 5 cos (t) + C

\frac{0.625}{s + 4}

x \to 0 lim (\frac{x ^{2} + 2 x - 99}{x})

\int \frac{2 x}{1 + x ^{4}} d x

y = (x + 3)^{3}

x^{2} y^{^{''}} + x y^{^{'}} - y = \frac{ln ( x )}{x ^{2}}