What is the sum from n=1 to infinity of n/(2^n+5) ?

The sum from n=1 to infinity of n/(2^n+5) is converges

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sum from n=1 to infinity of n/(2^n+5)

n = 1 \sum \infty \frac{n}{2 ^{n} + 5}

converges

Solution steps

n = 1 \sum \infty \frac{n}{2 ^{n} + 5}

Apply Series Ratio Test:

converges

= converges

\frac{\partial}{\partial y} (- e^{x} cos (y))

\frac{d}{d x} ((x + 2)^{4} - (x + 2)^{- 2})

\frac{2}{s + 1} + \frac{8 s}{s ^{2} + 9}

\int_{1}^{\infty} \frac{1}{x ^{\frac{13}{12}}} d x

x \to 0 lim (\frac{e}{x})

What is the sum from n=1 to infinity of n/(2^n+5) ?
The sum from n=1 to infinity of n/(2^n+5) is converges