What is (\partial)/(\partial y)(-e^xcos(y)) ?

The answer to (\partial)/(\partial y)(-e^xcos(y)) is e^xsin(y)

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(\partial)/(\partial y)(-e^xcos(y))

\frac{\partial}{\partial y} (- e^{x} cos (y))

e^{x} sin (y)

Solution steps

\frac{\partial}{\partial y} (- e^{x} cos (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - e^{x} \frac{\partial}{\partial y} (cos (y))

Apply the common derivative:

\frac{\partial}{\partial y} (cos (y)) = - sin (y)

= - e^{x} (- sin (y))

Simplify

= e^{x} sin (y)

\frac{d}{d x} ((x + 2)^{4} - (x + 2)^{- 2})

\frac{2}{s + 1} + \frac{8 s}{s ^{2} + 9}

\int_{1}^{\infty} \frac{1}{x ^{\frac{13}{12}}} d x

x \to 0 lim (\frac{e}{x})

\int \frac{1}{( x + y )} d x

What is (\partial)/(\partial y)(-e^xcos(y)) ?
The answer to (\partial)/(\partial y)(-e^xcos(y)) is e^xsin(y)