What is the integral of 1/((x+y)) ?

The integral of 1/((x+y)) is ln|y+x|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/((x+y))

\int \frac{1}{( x + y )} d x

ln ∣ y + x ∣ + C

Solution steps

\int \frac{1}{x + y} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = y + x

= ln ∣ y + x ∣

Add a constant to the solution

= ln ∣ y + x ∣ + C

\int (x^{3} - 9 x) d x

\int 4 cos^{3} (x) d x

\frac{d}{d x} (- 6 b^{2} x (a^{2} - b^{2} x^{2})^{2})

(x + 1)^{3}

t