What is the derivative of e^{2ln(x}) ?

The derivative of e^{2ln(x}) is 2x

What is the first derivative of e^{2ln(x}) ?

The first derivative of e^{2ln(x}) is 2x

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\frac{d}{d x} (e^{2 l n (x)})

2 x

Solution steps

\frac{d}{d x} (e^{2 l n (x)})

Simplify

e^{2 l n (x)} : x^{2}

= \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 x^{2 - 1}

Simplify

= 2 x

\frac{d x}{d t} + 4 t^{3} x^{5} + \frac{x}{t} = 0

\frac{d}{d x} ((x - \frac{1}{x})^{4})

x \to 5 lim (- x^{2} + 8 x - 5)

\int_{0}^{4} (e^{x})^{2} d x

\frac{\partial}{\partial z} (3 y z^{2})

What is the derivative of e^{2ln(x}) ?
The derivative of e^{2ln(x}) is 2x
What is the first derivative of e^{2ln(x}) ?
The first derivative of e^{2ln(x}) is 2x