What is the tangent of f(x)=2cos(x),\at x= pi/3 ?

The tangent of f(x)=2cos(x),\at x= pi/3 is y=-sqrt(3)x+1+pi/(sqrt(3))

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tangent of f(x)=2cos(x),\at x= pi/3

tangent of

f (x) = 2 cos (x), at x = \frac{π}{3}

y = - 3 x + 1 + \frac{π}{3}

Solution steps

Find the tangent point:

(\frac{π}{3}, 1)

Find the slope of

f (x) = 2 cos (x) : \frac{df ( x )}{d x} = - 2 sin (x)

Compute the slope of

f (x) = 2 cos (x)

x = \frac{π}{3} : m = - 3

Find the line with slope m=

- 3

and passing through

(\frac{π}{3}, 1) : y = - 3 x + 1 + \frac{π}{3}

y = - 3 x + 1 + \frac{π}{3}

\frac{d}{d x} (x^{2} + 15)

x \to - 2 lim (- 7)

\int (4 x + 3) (2 x^{2} + 3 x) d x

(x + 1)^{2} (x^{2} + 1)^{- 3}

\frac{\partial}{\partial x} (a cos (x))

What is the tangent of f(x)=2cos(x),\at x= pi/3 ?
The tangent of f(x)=2cos(x),\at x= pi/3 is y=-sqrt(3)x+1+pi/(sqrt(3))