What is (\partial)/(\partial x)(acos(x)) ?

The answer to (\partial)/(\partial x)(acos(x)) is -asin(x)

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(\partial)/(\partial x)(acos(x))

\frac{\partial}{\partial x} (a cos (x))

- a sin (x)

Solution steps

\frac{\partial}{\partial x} (a cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= a \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= a (- sin (x))

Simplify

= - a sin (x)

x \to 0 + lim (\frac{x - 2}{∣ x ∣})

T

\frac{d}{d x} (\frac{1}{2} - \frac{1}{2 x})

x \to 0 - lim (2 x - 8 x^{2})

y^{^{''}} - 2 y + y = \frac{e ^{x}}{1 + x ^{2}}

What is (\partial)/(\partial x)(acos(x)) ?
The answer to (\partial)/(\partial x)(acos(x)) is -asin(x)