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Popular >

2y^{''}+y^'-y=0

Solution

2 y^{^{''}} + y^{^{'}} - y = 0

Solution

y = c_{1} e^{\frac{t}{2}} + c_{2} e^{- t}

Solution steps

2 y^{''} (t) + y^{'} (t) - y = 0

Solve linear ODE:

y = c_{1} e^{\frac{t}{2}} + c_{2} e^{- t}

y = c_{1} e^{\frac{t}{2}} + c_{2} e^{- t}

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Frequently Asked Questions (FAQ)

What is the solution for 2y^{''}+y^'-y=0 ?
The solution for 2y^{''}+y^'-y=0 is y=c_{1}e^{t/2}+c_{2}e^{-t}