What is the limit as x approaches 0.99 of 2x^2-5x+1 ?

The limit as x approaches 0.99 of 2x^2-5x+1 is -1.9898

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0.99 of 2x^2-5x+1

x \to 0.99 lim (2 x^{2} - 5 x + 1)

- 1.9898

Solution steps

x \to 0.99 lim (2 x^{2} - 5 x + 1)

Plug in the value

x = 0.99

= 2 \cdot 0.9 9^{2} - 5 \cdot 0.99 + 1

Simplify

2 \cdot 0.9 9^{2} - 5 \cdot 0.99 + 1 : - 1.9898

= - 1.9898

\int 2 tan (x) d x

\int (1 - cot (x)) csc^{2} (x) d x

\frac{d}{d θ} (- 6 sin (θ))

\frac{d}{d x} (- \frac{1}{( 2 x + 8 ) ^{\frac{3}{2}}})

\int + \frac{1}{x ^{2}} d x

What is the limit as x approaches 0.99 of 2x^2-5x+1 ?
The limit as x approaches 0.99 of 2x^2-5x+1 is -1.9898