What is the derivative of 9e^x+2/(\sqrt[3]{x)} ?

The derivative of 9e^x+2/(\sqrt[3]{x)} is 9e^x-2/(3x^{4/3)}

What is the first derivative of 9e^x+2/(\sqrt[3]{x)} ?

The first derivative of 9e^x+2/(\sqrt[3]{x)} is 9e^x-2/(3x^{4/3)}

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derivative of

9 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (9 e^{x}) = 9 e^{x}

= 9 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

\int \frac{x + 21}{x ^{2} + 28 x + 200} d x

\int 4^{x} + ln (5^{x}) d x

\frac{3}{s ^{2} + 7}

\int 8 x d x

y = 16 x, (16, 64)

What is the derivative of 9e^x+2/(\sqrt[3]{x)} ?
The derivative of 9e^x+2/(\sqrt[3]{x)} is 9e^x-2/(3x^{4/3)}
What is the first derivative of 9e^x+2/(\sqrt[3]{x)} ?
The first derivative of 9e^x+2/(\sqrt[3]{x)} is 9e^x-2/(3x^{4/3)}