What is the derivative of 1/(x+7) ?

The derivative of 1/(x+7) is -1/((x+7)^2)

What is the first derivative of 1/(x+7) ?

The first derivative of 1/(x+7) is -1/((x+7)^2)

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\frac{d}{d x} (\frac{1}{x + 7})

- \frac{1}{( x + 7 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x + 7})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 7)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 7 ) ^{2}} \frac{d}{d x} (x + 7)

= - \frac{1}{( x + 7 ) ^{2}} \frac{d}{d x} (x + 7)

\frac{d}{d x} (x + 7) = 1

= - \frac{1}{( x + 7 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x + 7 ) ^{2}}

\int x^{2} x + 22 d x

x \to 0 lim (a x + b)

\int_{0}^{10} e^{x} sin (x) d x

\frac{d}{d x} ((\frac{x ^{2} + 1}{x ^{2} - 1})^{6})

x \to 3 - lim (x^{2})

What is the derivative of 1/(x+7) ?
The derivative of 1/(x+7) is -1/((x+7)^2)
What is the first derivative of 1/(x+7) ?
The first derivative of 1/(x+7) is -1/((x+7)^2)