What is the derivative of 2x^2+3x ?

The derivative of 2x^2+3x is 4x+3

What is the first derivative of 2x^2+3x ?

The first derivative of 2x^2+3x is 4x+3

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\frac{d}{d x} (2 x^{2} + 3 x)

4 x + 3

Solution steps

\frac{d}{d x} (2 x^{2} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

= 4 x + 3

\int (\frac{5}{3})^{x} d x

\frac{d}{d x} (e^{- x} + 1)

\frac{d}{d t} (\frac{1}{t})

\int sec (x) (sec (x) - tan (x)) d x

\int_{0}^{1} 1 + (x)^{2} d x

What is the derivative of 2x^2+3x ?
The derivative of 2x^2+3x is 4x+3
What is the first derivative of 2x^2+3x ?
The first derivative of 2x^2+3x is 4x+3