What is the derivative of 9tan(x-9cot(x)) ?

The derivative of 9tan(x-9cot(x)) is 9sec^2(x)+9csc^2(x)

What is the first derivative of 9tan(x-9cot(x)) ?

The first derivative of 9tan(x-9cot(x)) is 9sec^2(x)+9csc^2(x)

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\frac{d}{d x} (9 tan (x) - 9 cot (x))

9 sec^{2} (x) + 9 csc^{2} (x)

Solution steps

\frac{d}{d x} (9 tan (x) - 9 cot (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 tan (x)) - \frac{d}{d x} (9 cot (x))

\frac{d}{d x} (9 tan (x)) = 9 sec^{2} (x)

\frac{d}{d x} (9 cot (x)) = - 9 csc^{2} (x)

= 9 sec^{2} (x) - (- 9 csc^{2} (x))

Simplify

= 9 sec^{2} (x) + 9 csc^{2} (x)

\frac{d}{d x} (x (17 - 2 x) (33 - 2 x))

x \to 0 lim (2 x^{2} + 4 x - 2)

1 2^{^{'}}

x \to 1 lim (\frac{2}{x ^{2} - 1})

x \to - 0 lim (f (x))

What is the derivative of 9tan(x-9cot(x)) ?
The derivative of 9tan(x-9cot(x)) is 9sec^2(x)+9csc^2(x)
What is the first derivative of 9tan(x-9cot(x)) ?
The first derivative of 9tan(x-9cot(x)) is 9sec^2(x)+9csc^2(x)