What is the integral of (2x)/(1+2x^2) ?

The integral of (2x)/(1+2x^2) is 1/2 ln|1+2x^2|+C

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integral of (2x)/(1+2x^2)

\int \frac{2 x}{1 + 2 x ^{2}} d x

\frac{1}{2} ln 1 + 2 x^{2} + C

Solution steps

\int \frac{2 x}{1 + 2 x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{x}{1 + 2 x ^{2}} d x

Apply u-substitution

: \int \frac{1}{4 u} d u

= 2 \cdot \int \frac{1}{4 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{4} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 2 \cdot \frac{1}{4} ln ∣ u ∣

Substitute back

u = 1 + 2 x^{2}

= 2 \cdot \frac{1}{4} ln 1 + 2 x^{2}

Simplify

2 \cdot \frac{1}{4} ln 1 + 2 x^{2} : \frac{1}{2} ln 1 + 2 x^{2}

= \frac{1}{2} ln 1 + 2 x^{2}

Add a constant to the solution

= \frac{1}{2} ln 1 + 2 x^{2} + C

f (x) = (5 x - 1)^{4}, at x = 2

\frac{\partial}{\partial x} (x^{2} \cdot e^{x})

y = x^{2}, y = \frac{2}{( x ^{2} + 1 )}

\int \frac{1}{x ^{2}} 2 - \frac{1}{x} d x

(19 - (15 - 2 x^{4})^{7})^{3}

What is the integral of (2x)/(1+2x^2) ?
The integral of (2x)/(1+2x^2) is 1/2 ln|1+2x^2|+C