What is (\partial)/(\partial y)(3ycos(x)) ?

The answer to (\partial)/(\partial y)(3ycos(x)) is 3cos(x)

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(\partial)/(\partial y)(3ycos(x))

\frac{\partial}{\partial y} (3 y cos (x))

3 cos (x)

Solution steps

\frac{\partial}{\partial y} (3 y cos (x))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 cos (x) \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= 3 cos (x) \cdot 1

Simplify

= 3 cos (x)

(2 x y + x^{3}) y^{^{'}} = \frac{1}{2} x^{2} y + y^{2}

x \to - 4 lim (9 x + 11)

\int 30 (1 + t) d t

\frac{\partial}{\partial y} (x^{3} y + e^{x y^{2}})

\int_{0}^{1} ln (7 x) d x

What is (\partial)/(\partial y)(3ycos(x)) ?
The answer to (\partial)/(\partial y)(3ycos(x)) is 3cos(x)