What is the integral from 0 to 1 of ln(7x) ?

The integral from 0 to 1 of ln(7x) is ln(7)-1

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integral from 0 to 1 of ln(7x)

\int_{0}^{1} ln (7 x) d x

ln (7) - 1

Decimal Notation

0.94591 \dots

Solution steps

\int_{0}^{1} ln (7 x) d x

Apply Integration By Parts

: [x ln (7 x) - \int 1 d x]_{0}^{1}

= [x ln (7 x) - \int 1 d x]_{0}^{1}

\int 1 d x = x

= [x ln (7 x) - x]_{0}^{1}

Compute the boundaries:

ln (7) - 1

= ln (7) - 1

n = 0 \sum \infty \frac{( - 1 ) ^{n} 7 ^{n} x ^{n}}{5 ^{n + 1}}

\int_{2}^{\infty} 2 e^{- 2 x} d x

\int 2 b x^{3} d x

\frac{d}{d x} ((5 x^{2} - 7) (3 x^{2} - 2 x + 1))

y = \frac{x}{4 - x}, (3, 3)

What is the integral from 0 to 1 of ln(7x) ?
The integral from 0 to 1 of ln(7x) is ln(7)-1