What is the tangent of y= x/(sqrt(4-x)),(3,3) ?

The tangent of y= x/(sqrt(4-x)),(3,3) is y= 5/2 x-9/2

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tangent of y= x/(sqrt(4-x)),(3,3)

tangent of

y = \frac{x}{4 - x}, (3, 3)

y = \frac{5}{2} x - \frac{9}{2}

Solution steps

Find the slope of

y = \frac{x}{4 - x} : \frac{d y}{d x} = \frac{8 - x}{2 ( 4 - x ) 4 - x}

Compute the slope of

y = \frac{x}{4 - x}

(3, 3) : m = \frac{5}{2}

Find the line with slope m=

\frac{5}{2}

and passing through

(3, 3) : y = \frac{5}{2} x - \frac{9}{2}

y = \frac{5}{2} x - \frac{9}{2}

\frac{d}{d x} ((x - 2)^{2} - ln (x))

- \frac{1}{4 x ^{\frac{3}{2}}}

\frac{d}{d x} (sin (1 - x))

\int \frac{sin ( 2 x )}{5 + cos ^{2} ( x )} d x

x \to - \infty lim (- x^{3})

What is the tangent of y= x/(sqrt(4-x)),(3,3) ?
The tangent of y= x/(sqrt(4-x)),(3,3) is y= 5/2 x-9/2