What is the derivative of (x-2^2-ln(x)) ?

The derivative of (x-2^2-ln(x)) is 2(x-2)-1/x

What is the first derivative of (x-2^2-ln(x)) ?

The first derivative of (x-2^2-ln(x)) is 2(x-2)-1/x

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\frac{d}{d x} ((x - 2)^{2} - ln (x))

2 (x - 2) - \frac{1}{x}

Solution steps

\frac{d}{d x} ((x - 2)^{2} - ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} ((x - 2)^{2}) - \frac{d}{d x} (ln (x))

\frac{d}{d x} ((x - 2)^{2}) = 2 (x - 2)

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 2 (x - 2) - \frac{1}{x}

- \frac{1}{4 x ^{\frac{3}{2}}}

\frac{d}{d x} (sin (1 - x))

\int \frac{sin ( 2 x )}{5 + cos ^{2} ( x )} d x

x \to - \infty lim (- x^{3})

\frac{\partial}{\partial y} (x^{a} y^{1 - a})

What is the derivative of (x-2^2-ln(x)) ?
The derivative of (x-2^2-ln(x)) is 2(x-2)-1/x
What is the first derivative of (x-2^2-ln(x)) ?
The first derivative of (x-2^2-ln(x)) is 2(x-2)-1/x