What is the tangent of f(x)=sqrt(6x),(6,6) ?

The tangent of f(x)=sqrt(6x),(6,6) is y= 1/2 x+3

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tangent of f(x)=sqrt(6x),(6,6)

tangent of

f (x) = 6 x, (6, 6)

y = \frac{1}{2} x + 3

Solution steps

Find the slope of

f (x) = 6 x : \frac{df ( x )}{d x} = \frac{3}{2 x}

Compute the slope of

f (x) = 6 x

(6, 6) : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(6, 6) : y = \frac{1}{2} x + 3

y = \frac{1}{2} x + 3

\frac{30 s + 102}{s ^{2} + 4 s + 40}

\int_{4}^{\infty} e^{- 4 x} d x

\frac{d}{d x} ((4 x - 2)^{2})

\frac{\partial}{\partial s} (\frac{( s - 3 r )}{t})

\frac{d}{d x} (sin^{2} (x) + cos (x))

What is the tangent of f(x)=sqrt(6x),(6,6) ?
The tangent of f(x)=sqrt(6x),(6,6) is y= 1/2 x+3