What is the sum from n=1 to infinity of 1/(n-1) ?

The sum from n=1 to infinity of 1/(n-1) is diverges

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sum from n=1 to infinity of 1/(n-1)

n = 1 \sum \infty \frac{1}{n - 1}

diverges

Solution steps

n = 2 \sum \infty \frac{1}{n - 1}

Apply Series Comparison Test:

diverges

= diverges

\frac{1 - 4 t}{1 + 3 t}

x \to 1 lim (1 + cos (π) x)

\int_{0}^{1} (2 t - 1)^{2} d t

\frac{d}{d x} (sin^{2} (5 x - 3))

\frac{d y}{d x} + \frac{5}{x} \cdot y = 0

What is the sum from n=1 to infinity of 1/(n-1) ?
The sum from n=1 to infinity of 1/(n-1) is diverges