What is (\partial)/(\partial x)(-e^{-y/x}) ?

The answer to (\partial)/(\partial x)(-e^{-y/x}) is -(e^{-y/x}y)/(x^2)

Popular >

(\partial)/(\partial x)(-e^{-y/x})

\frac{\partial}{\partial x} (- e^{- \frac{y}{x}})

- \frac{e ^{- \frac{y}{x}} y}{x ^{2}}

Solution steps

\frac{\partial}{\partial x} (- e^{- \frac{y}{x}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{\partial}{\partial x} (e^{- \frac{y}{x}})

Apply the chain rule:

e^{- \frac{y}{x}} \frac{\partial}{\partial x} (- \frac{y}{x})

= e^{- \frac{y}{x}} \frac{\partial}{\partial x} (- \frac{y}{x})

\frac{\partial}{\partial x} (- \frac{y}{x}) = \frac{y}{x ^{2}}

= - e^{- \frac{y}{x}} \frac{y}{x ^{2}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{e ^{- \frac{y}{x}} y}{x ^{2}}

\int \frac{3 ^{l n (x)}}{x} d x

\frac{\partial}{\partial u} (v^{2})

\int \frac{1}{( x ^{2} ) ^{2}} d (x^{2})^{2}

\frac{\partial}{\partial x} (2 x^{4} y + cos (x^{3}))

\int_{7}^{8} \frac{1}{x ^{2} - 1} d x

What is (\partial)/(\partial x)(-e^{-y/x}) ?
The answer to (\partial)/(\partial x)(-e^{-y/x}) is -(e^{-y/x}y)/(x^2)