What is the integral of 1/((x^2)^2)x^2)^2 ?

The integral of 1/((x^2)^2)x^2)^2 is 1+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/((x^2)^2)x^2)^2

\int \frac{1}{( ( ( x ^{2} ) ^{2} ) ^{2} ) ^{2}} d (((x^{2})^{2})^{2})^{2}

1 + C

Solution steps

\int \frac{1}{( ( ( x ^{2} ) ^{2} ) ^{2} ) ^{2}} d (((x^{2})^{2})^{2})^{2}

(((x^{2})^{2})^{2})^{2} = x^{16}

= \int \frac{1}{x ^{16}} d (((x^{2})^{2})^{2})^{2}

Integral of a constant:

\int a d x = a x

= \frac{1}{x ^{16}} (((x^{2})^{2})^{2})^{2}

Simplify

\frac{1}{x ^{16}} (((x^{2})^{2})^{2})^{2} : 1

= 1

Add a constant to the solution

= 1 + C

\frac{\partial}{\partial x} (2 x^{4} y + cos (x^{3}))

\int_{7}^{8} \frac{1}{x ^{2} - 1} d x

\int \frac{9}{x ( x - 9 ) ^{2}} d x

\int (tan^{2} (x) 4) d x

\frac{d}{d x} (e^{2 x^{6}} - 1)

What is the integral of 1/((x^2)^2)x^2)^2 ?
The integral of 1/((x^2)^2)x^2)^2 is 1+C