What is (\partial)/(\partial x)(x^2-2xy+y) ?

The answer to (\partial)/(\partial x)(x^2-2xy+y) is 2x-2y

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(\partial)/(\partial x)(x^2-2xy+y)

\frac{\partial}{\partial x} (x^{2} - 2 x y + y)

2 x - 2 y

Solution steps

\frac{\partial}{\partial x} (x^{2} - 2 x y + y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (2 x y) + \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (y) = 0

= 2 x - 2 y + 0

Simplify

= 2 x - 2 y

(0, 0), (8, 6)

n = 0 \sum \infty (1.67)^{n}

\frac{d y}{d x}, y^{9} = x^{8}

\int (x^{2} - 8)^{3} (2 x) d x

\int_{1}^{\infty} x^{- 7} d x

What is (\partial)/(\partial x)(x^2-2xy+y) ?
The answer to (\partial)/(\partial x)(x^2-2xy+y) is 2x-2y