What is (\partial)/(\partial x)(cos(2y-3x)) ?

The answer to (\partial)/(\partial x)(cos(2y-3x)) is 3sin(2y-3x)

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(\partial)/(\partial x)(cos(2y-3x))

\frac{\partial}{\partial x} (cos (2 y - 3 x))

3 sin (2 y - 3 x)

Solution steps

\frac{\partial}{\partial x} (cos (2 y - 3 x))

Treat

y

as a constant

Apply the chain rule:

- sin (2 y - 3 x) \frac{\partial}{\partial x} (2 y - 3 x)

= - sin (2 y - 3 x) \frac{\partial}{\partial x} (2 y - 3 x)

\frac{\partial}{\partial x} (2 y - 3 x) = - 3

= - sin (2 y - 3 x) (- 3)

Simplify

= 3 sin (2 y - 3 x)

\int (2 x + 1) ln (x + 1) d x

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\int \frac{x}{2 y ^{4}} d x

\frac{d}{d x} (\frac{3 sin ( x )}{2 + cos ( x )})

\int_{0}^{2} 4 t d t

What is (\partial)/(\partial x)(cos(2y-3x)) ?
The answer to (\partial)/(\partial x)(cos(2y-3x)) is 3sin(2y-3x)