What is the integral of 2sqrt(x-2) ?

The integral of 2sqrt(x-2) is 4/3 (x-2)^{3/2}+C

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integral of 2sqrt(x-2)

\int 2 x - 2 d x

\frac{4}{3} (x - 2)^{\frac{3}{2}} + C

Solution steps

\int 2 x - 2 d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x - 2 d x

Apply u-substitution

: \int u d u

= 2 \cdot \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= 2 \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = x - 2

= 2 \cdot \frac{2}{3} (x - 2)^{\frac{3}{2}}

Simplify

2 \cdot \frac{2}{3} (x - 2)^{\frac{3}{2}} : \frac{4}{3} (x - 2)^{\frac{3}{2}}

= \frac{4}{3} (x - 2)^{\frac{3}{2}}

Add a constant to the solution

= \frac{4}{3} (x - 2)^{\frac{3}{2}} + C

y^{^{'}} + \frac{y}{t} = t^{2} y^{4}

x^{2} + 5 x, at x = 4

x \to + 4 + lim (\frac{7}{x - 4})

\int 1 - 25 x^{2} d x

\int \frac{20 x ^{4}}{4 x ^{5} + 3} d x

What is the integral of 2sqrt(x-2) ?
The integral of 2sqrt(x-2) is 4/3 (x-2)^{3/2}+C