What is the derivative of-4x^{-3} ?

The derivative of-4x^{-3} is (12)/(x^4)

What is the first derivative of-4x^{-3} ?

The first derivative of-4x^{-3} is (12)/(x^4)

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\frac{d}{d x} (- 4 x^{- 3})

\frac{12}{x ^{4}}

Solution steps

\frac{d}{d x} (- 4 x^{- 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 4 (- 3 x^{- 3 - 1})

Simplify

- 4 (- 3 x^{- 3 - 1}) : \frac{12}{x ^{4}}

= \frac{12}{x ^{4}}

\int 11 x^{\frac{4}{7}} + 7 x^{- \frac{6}{7}} d x

y = x^{4}

\int \frac{x}{4} 16 + x^{2} d x

x \to 0 - lim (\frac{1}{e ^{x} + 1})

\frac{d}{d x} (\frac{x ^{3}}{6} - \frac{3 x ^{2}}{2})

What is the derivative of-4x^{-3} ?
The derivative of-4x^{-3} is (12)/(x^4)
What is the first derivative of-4x^{-3} ?
The first derivative of-4x^{-3} is (12)/(x^4)