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Popular >

yy^'=(y^2-y)(2x+5)

Solution

y y^{^{'}} = (y^{2} - y) (2 x + 5)

Solution

y = e^{x^{2} + 5 x + c_{1}} + 1

Solution steps

y y^{'} (x) = (y^{2} - y) (2 x + 5)

Solve separable ODE:

y = e^{x^{2} + 5 x + c_{1}} + 1

y = e^{x^{2} + 5 x + c_{1}} + 1

Popular Examples

integral of sin(3x)-cos(3x)

\int sin (3 x) - cos (3 x) d x

y^{''}+4y^'+5y=10

y^{^{''}} + 4 y^{^{'}} + 5 y = 10

derivative of 3x^2+2e^x

\frac{d}{d x} (3 x^{2} + 2 e^{x})

derivative of h(x)=sec(-4x^2-3x+2)derivative of

h (x) = sec (- 4 x^{2} - 3 x + 2)

normal of f(x)=3sin(2x),\at x= pi/8 normal of

f (x) = 3 sin (2 x), at x = \frac{π}{8}

Frequently Asked Questions (FAQ)

What is the solution for yy^'=(y^2-y)(2x+5) ?
The solution for yy^'=(y^2-y)(2x+5) is y=e^{x^2+5x+c_{1}}+1