What is the normal of f(x)=3sin(2x),\at x= pi/8 ?

The normal of f(x)=3sin(2x),\at x= pi/8 is f(x)=-1/(3sqrt(2))x+3/(sqrt(2))+pi/(24sqrt(2))

Popular >

normal of f(x)=3sin(2x),\at x= pi/8

normal of

f (x) = 3 sin (2 x), at x = \frac{π}{8}

f (x) = - \frac{1}{3 2} x + \frac{3}{2} + \frac{π}{24 2}

Solution steps

Find the tangent point:

(\frac{π}{8}, \frac{3}{2})

Find the slope of

f (x) = 3 sin (2 x) : \frac{df ( x )}{d x} = 6 cos (2 x)

Compute the slope of

f (x) = 3 sin (2 x)

x = \frac{π}{8} : m = 32

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{3 2}

Find the line with slope m=

- \frac{1}{3 2}

and passing through

(\frac{π}{8}, \frac{3}{2}) : f (x) = - \frac{1}{3 2} x + \frac{3}{2} + \frac{π}{24 2}

f (x) = - \frac{1}{3 2} x + \frac{3}{2} + \frac{π}{24 2}

x \frac{d y}{d x} = 5 x e^{x} - y + 9 x^{2}

\int \frac{ln ( x ) + 3}{x ( ln ( x ) - 1 )} d x

sin (t - 5)

y = (3 x^{2} + 3 x - 1)^{4}

(x^{2} - 3 y^{2}) d x + (2 x y) d y = 0

What is the normal of f(x)=3sin(2x),\at x= pi/8 ?
The normal of f(x)=3sin(2x),\at x= pi/8 is f(x)=-1/(3sqrt(2))x+3/(sqrt(2))+pi/(24sqrt(2))