What is the derivative of (x^2/(sqrt(x^4+x^2+1))) ?

The derivative of (x^2/(sqrt(x^4+x^2+1))) is (x^3+2x)/((x^4+x^2+1)sqrt(x^4+x^2+1))

What is the first derivative of (x^2/(sqrt(x^4+x^2+1))) ?

The first derivative of (x^2/(sqrt(x^4+x^2+1))) is (x^3+2x)/((x^4+x^2+1)sqrt(x^4+x^2+1))

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\frac{d}{d x} (\frac{x ^{2}}{x ^{4} + x ^{2} + 1})

\frac{x ^{3} + 2 x}{( x ^{4} + x ^{2} + 1 ) x ^{4} + x ^{2} + 1}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{x ^{4} + x ^{2} + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) x ^{4} + x ^{2} + 1 - \frac{d}{d x} ( x ^{4} + x ^{2} + 1 ) x ^{2}}{( x ^{4} + x ^{2} + 1 ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x^{4} + x^{2} + 1) = \frac{x ( 2 x ^{2} + 1 )}{x ^{4} + x ^{2} + 1}

= \frac{2 x x ^{4} + x ^{2} + 1 - \frac{x ( 2 x ^{2} + 1 )}{x ^{4} + x ^{2} + 1} x ^{2}}{( x ^{4} + x ^{2} + 1 ) ^{2}}

Simplify

\frac{2 x x ^{4} + x ^{2} + 1 - \frac{x ( 2 x ^{2} + 1 )}{x ^{4} + x ^{2} + 1} x ^{2}}{( x ^{4} + x ^{2} + 1 ) ^{2}} : \frac{x ^{3} + 2 x}{( x ^{4} + x ^{2} + 1 ) x ^{4} + x ^{2} + 1}

= \frac{x ^{3} + 2 x}{( x ^{4} + x ^{2} + 1 ) x ^{4} + x ^{2} + 1}

\frac{d}{d x} (arcsin (sin (x) - cos (x)))

\frac{10 x ^{3}}{3} + \frac{13 x ^{2}}{2} + 4 x + 16

\int cos (\frac{t}{2}) d t

\frac{d}{d x} (x^{2} - 8 x + 13)

\frac{d}{d x} (\frac{2 x}{x ^{2}})

What is the derivative of (x^2/(sqrt(x^4+x^2+1))) ?
The derivative of (x^2/(sqrt(x^4+x^2+1))) is (x^3+2x)/((x^4+x^2+1)sqrt(x^4+x^2+1))
What is the first derivative of (x^2/(sqrt(x^4+x^2+1))) ?
The first derivative of (x^2/(sqrt(x^4+x^2+1))) is (x^3+2x)/((x^4+x^2+1)sqrt(x^4+x^2+1))