What is the slope of (-10/63 , 1/3),(2/3 ,-11/45) ?

The slope of (-10/63 , 1/3),(2/3 ,-11/45) is m=-7/10

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slope of (-10/63 , 1/3),(2/3 ,-11/45)

slope

(- \frac{10}{63}, \frac{1}{3}), (\frac{2}{3}, - \frac{11}{45})

m = - \frac{7}{10}

Solution steps

Slope between two points: Slope

= \frac{y _{2} - y _{1}}{x _{2} - x _{1}}

(x_{1}, y_{1}) = (- \frac{10}{63}, \frac{1}{3}), (x_{2}, y_{2}) = (\frac{2}{3}, - \frac{11}{45})

m = \frac{- \frac{11}{45} - \frac{1}{3}}{\frac{2}{3} - ( - \frac{10}{63} )}

Refine

m = - \frac{7}{10}

f (x) = \frac{( 2 - e ^{x} + 2 x )}{3}

\int x y d x

(7, - 7), (5, - 3)

(- 6, - 5), (2, - 10)

h \to 0 lim (\frac{( cos ( x + h ) - cos ( x ) )}{h})

What is the slope of (-10/63 , 1/3),(2/3 ,-11/45) ?
The slope of (-10/63 , 1/3),(2/3 ,-11/45) is m=-7/10