What is the derivative of 3x^2-4x+5 ?

The derivative of 3x^2-4x+5 is 6x-4

What is the first derivative of 3x^2-4x+5 ?

The first derivative of 3x^2-4x+5 is 6x-4

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\frac{d}{d x} (3 x^{2} - 4 x + 5)

6 x - 4

Solution steps

\frac{d}{d x} (3 x^{2} - 4 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (5)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (5) = 0

= 6 x - 4 + 0

Simplify

= 6 x - 4

\int_{- 1}^{1} \frac{1}{1 + x ^{2}} d x

t y^{^{'}} + 4 y = t^{2} - t + 7

t^{2} sin^{2} (t)

\frac{d y}{d x} = \frac{x}{25 y}, y (0) = - 5

2.5 (1 + e^{- 0.1 t})

What is the derivative of 3x^2-4x+5 ?
The derivative of 3x^2-4x+5 is 6x-4
What is the first derivative of 3x^2-4x+5 ?
The first derivative of 3x^2-4x+5 is 6x-4