What is the solution for (dy)/(dx)= x/(25y),y(0)=-5 ?

The solution for (dy)/(dx)= x/(25y),y(0)=-5 is y=-(sqrt(625+x^2))/5

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(dy)/(dx)= x/(25y),y(0)=-5

\frac{d y}{d x} = \frac{x}{25 y}, y (0) = - 5

y = - \frac{625 + x ^{2}}{5}

Solution steps

\frac{d y}{d x} = \frac{x}{25 y}

Solve separable ODE:

y = - \frac{625 + x ^{2}}{5}

y = - \frac{625 + x ^{2}}{5}

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\frac{d ^{2}}{d x ^{2}} (sin (3 x))

\int 3 sin^{3} (x co) s^{7} x d x

\frac{( 5 t + 300 )}{t ^{2}} + 25

\frac{d}{d x} (x^{5} (x^{6} + 1))

What is the solution for (dy)/(dx)= x/(25y),y(0)=-5 ?
The solution for (dy)/(dx)= x/(25y),y(0)=-5 is y=-(sqrt(625+x^2))/5