What is the derivative of 5ln(2+x) ?

The derivative of 5ln(2+x) is 5/(2+x)

What is the first derivative of 5ln(2+x) ?

The first derivative of 5ln(2+x) is 5/(2+x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (5 ln (2 + x))

\frac{5}{2 + x}

Solution steps

\frac{d}{d x} (5 ln (2 + x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (ln (2 + x))

Apply the chain rule:

\frac{1}{2 + x} \frac{d}{d x} (2 + x)

= \frac{1}{2 + x} \frac{d}{d x} (2 + x)

\frac{d}{d x} (2 + x) = 1

= 5 \cdot \frac{1}{2 + x} \cdot 1

Simplify

5 \cdot \frac{1}{2 + x} \cdot 1 : \frac{5}{2 + x}

= \frac{5}{2 + x}

x \to 1 lim (\frac{x ^{3} - 1}{x + 1})

\int (6 x^{2}) d x

\frac{d}{d x} (\frac{x ^{2} + 3}{cos ( x )})

y = arctan (\frac{x}{4}), (4, \frac{π}{4})

\frac{\partial}{\partial x} (x^{5} y)

What is the derivative of 5ln(2+x) ?
The derivative of 5ln(2+x) is 5/(2+x)
What is the first derivative of 5ln(2+x) ?
The first derivative of 5ln(2+x) is 5/(2+x)