What is the tangent of y=arctan(x/4),(4, pi/4) ?

The tangent of y=arctan(x/4),(4, pi/4) is y= 1/8 x+pi/4-1/2

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tangent of y=arctan(x/4),(4, pi/4)

tangent of

y = arctan (\frac{x}{4}), (4, \frac{π}{4})

y = \frac{1}{8} x + \frac{π}{4} - \frac{1}{2}

Solution steps

Find the slope of

y = arctan (\frac{x}{4}) : \frac{d y}{d x} = \frac{4}{x ^{2} + 16}

Compute the slope of

y = arctan (\frac{x}{4})

(4, \frac{π}{4}) : m = \frac{1}{8}

Find the line with slope m=

\frac{1}{8}

and passing through

(4, \frac{π}{4}) : y = \frac{1}{8} x + \frac{π}{4} - \frac{1}{2}

y = \frac{1}{8} x + \frac{π}{4} - \frac{1}{2}

\frac{\partial}{\partial x} (x^{5} y)

\int \frac{4 x ^{2} + 2 x + 8}{x ( x ^{2} + 2 ) ^{2}} d x

x \to + 1 lim (- \frac{3}{x - 1})

x, at x = 25

\frac{\partial}{\partial x} (sin (- x) cos (4 y))

What is the tangent of y=arctan(x/4),(4, pi/4) ?
The tangent of y=arctan(x/4),(4, pi/4) is y= 1/8 x+pi/4-1/2