What is the derivative of x+y-1 ?

The derivative of x+y-1 is (dy)/(dx)+1

What is the first derivative of x+y-1 ?

The first derivative of x+y-1 is (dy)/(dx)+1

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\frac{d}{d x} (x + y - 1)

\frac{d y}{d x} + 1

Solution steps

\frac{d}{d x} (x + y - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d y}{d x} - \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 1 + \frac{d y}{d x} - 0

Simplify

= \frac{d y}{d x} + 1

\int (\frac{1}{2 x}) d x

y = 3 x, x = 0, x = 4

2^{y}

f (x) = (2 x - 1)^{3}, at x = 1

\int x^{- 2} e^{- x} d x

What is the derivative of x+y-1 ?
The derivative of x+y-1 is (dy)/(dx)+1
What is the first derivative of x+y-1 ?
The first derivative of x+y-1 is (dy)/(dx)+1