What is area y=sqrt(3x),x=0,x=4 ?

The answer to area y=sqrt(3x),x=0,x=4 is (16)/(sqrt(3))

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area y=sqrt(3x),x=0,x=4

area

y = 3 x, x = 0, x = 4

\frac{16}{3}

Decimal Notation

9.23760 \dots

Solution steps

Apply the area formula:

\int_{0}^{4} 3 x d x

Solve

\int_{0}^{4} 3 x d x : \frac{16}{3}

The area is:

= \frac{16}{3}

2^{y}

f (x) = (2 x - 1)^{3}, at x = 1

\int x^{- 2} e^{- x} d x

y^{^{''}} + 10 y^{^{'}} + 34 y = 0

x d y - y d x = 2 x^{2} y^{2} d y, y (1) = 2

What is area y=sqrt(3x),x=0,x=4 ?
The answer to area y=sqrt(3x),x=0,x=4 is (16)/(sqrt(3))