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Popular >

xdy-ydx=2x^2y^2dy,y(1)=2

Solution

x d y - y d x = 2 x^{2} y^{2} d y, y (1) = 2

Solution

x d y - \circ y^{2} d x

Solution steps

Find

x d y - y d x \circ y (1)

given

x d y - y d x (x, y) = 2 x^{2} y^{2} d y, y (1) = 2

Simplify

x d y - y d x \circ y \cdot 1 : x d y - \circ y^{2} d x

= x d y - \circ y^{2} d x

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\frac{\partial}{\partial x} (8 x cos (x) cos (y))

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x \to 1 lim (\frac{∣ x ∣}{x})

Frequently Asked Questions (FAQ)

What is the xdy-ydx=2x^2y^2dy,y(1)=2 ?
The xdy-ydx=2x^2y^2dy,y(1)=2 is xdy-\circ y^2dx