What is (\partial)/(\partial y)((2x-y+5)^2) ?

The answer to (\partial)/(\partial y)((2x-y+5)^2) is -2(2x-y+5)

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(\partial)/(\partial y)((2x-y+5)^2)

\frac{\partial}{\partial y} ((2 x - y + 5)^{2})

- 2 (2 x - y + 5)

Solution steps

\frac{\partial}{\partial y} ((2 x - y + 5)^{2})

Treat

x

as a constant

Apply the chain rule:

2 (2 x - y + 5) \frac{\partial}{\partial y} (2 x - y + 5)

= 2 (2 x - y + 5) \frac{\partial}{\partial y} (2 x - y + 5)

\frac{\partial}{\partial y} (2 x - y + 5) = - 1

= 2 (2 x - y + 5) (- 1)

Simplify

= - 2 (2 x - y + 5)

f (x) = (4 x^{2} - 5 x) e^{x}

\int 5 e^{- 4 x} d x

\frac{d}{d x} (arcsin (\frac{9}{x ^{2}}))

(\frac{4 x}{x ^{2} + 1})^{\frac{1}{4}}

f (x) = 4 x + 2

What is (\partial)/(\partial y)((2x-y+5)^2) ?
The answer to (\partial)/(\partial y)((2x-y+5)^2) is -2(2x-y+5)