What is the tangent of f(x)=sin(x)+1/2 ,\at (x=0) ?

The tangent of f(x)=sin(x)+1/2 ,\at (x=0) is y=x+1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=sin(x)+1/2 ,\at (x=0)

tangent of

f (x) = sin (x) + \frac{1}{2}, at (x = 0)

y = x + \frac{1}{2}

Solution steps

Find the tangent point:

(0, \frac{1}{2})

Find the slope of

f (x) = sin (x) + \frac{1}{2} : \frac{df ( x )}{d x} = cos (x)

Compute the slope of

f (x) = sin (x) + \frac{1}{2}

x = 0 : m = 1

Find the line with slope m=

1

and passing through

(0, \frac{1}{2}) : y = x + \frac{1}{2}

y = x + \frac{1}{2}

\int_{1}^{5} 9 3 v + 1 d v

\frac{d}{d x} (cos (2 x) + 2 x sin (2 x))

\frac{d x}{d t} = 3 x (8 - x)

\frac{d}{d x} (60 x^{4} - 160 x^{3} + 120 x^{2} - 20)

\frac{d}{d x} ((11 x^{2} - 22 x + 22) e^{x})

What is the tangent of f(x)=sin(x)+1/2 ,\at (x=0) ?
The tangent of f(x)=sin(x)+1/2 ,\at (x=0) is y=x+1/2