What is the derivative of (x^2-4/(x+2)) ?

The derivative of (x^2-4/(x+2)) is 1

What is the first derivative of (x^2-4/(x+2)) ?

The first derivative of (x^2-4/(x+2)) is 1

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\frac{d}{d x} (\frac{x ^{2} - 4}{x + 2})

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 4}{x + 2})

Simplify

\frac{x ^{2} - 4}{x + 2} : x - 2

= \frac{d}{d x} (x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (2)

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= 1 - 0

Simplify

= 1

\frac{d}{d x} (3 ln ∣ x - e^{x} ∣)

\int x^{2} \cdot (x - 5) + 7 - x d x

\int - 4 e^{x} d x

\int_{0}^{2} 2 π x (3 x (x - 2)^{2}) d x

n = 1 \sum \infty \frac{2 n}{3 n - 1}

What is the derivative of (x^2-4/(x+2)) ?
The derivative of (x^2-4/(x+2)) is 1
What is the first derivative of (x^2-4/(x+2)) ?
The first derivative of (x^2-4/(x+2)) is 1