What is the derivative of y=(x^2)/(1+sqrt(x)) ?

The derivative of y=(x^2)/(1+sqrt(x)) is (4x(1+sqrt(x))-x^{3/2})/(2(1+sqrt(x))^2)

What is the first derivative of y=(x^2)/(1+sqrt(x)) ?

The first derivative of y=(x^2)/(1+sqrt(x)) is (4x(1+sqrt(x))-x^{3/2})/(2(1+sqrt(x))^2)

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derivative of

y = \frac{x ^{2}}{1 + x}

\frac{4 x ( 1 + x ) - x ^{\frac{3}{2}}}{2 ( 1 + x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{1 + x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( 1 + x ) - \frac{d}{d x} ( 1 + x ) x ^{2}}{( 1 + x ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1 + x) = \frac{1}{2 x}

= \frac{2 x ( 1 + x ) - \frac{1}{2 x} x ^{2}}{( 1 + x ) ^{2}}

Simplify

\frac{2 x ( 1 + x ) - \frac{1}{2 x} x ^{2}}{( 1 + x ) ^{2}} : \frac{4 x ( 1 + x ) - x ^{\frac{3}{2}}}{2 ( 1 + x ) ^{2}}

= \frac{4 x ( 1 + x ) - x ^{\frac{3}{2}}}{2 ( 1 + x ) ^{2}}

x \to 0 lim (\frac{2 x}{x ^{2} + 1})

\int (\frac{sin ( x )}{x}) d x

\frac{\partial}{\partial x} (2 x - 3 yz)

\int_{0}^{1} (7 x^{e} + 2 e^{x}) d x

What is the derivative of y=(x^2)/(1+sqrt(x)) ?
The derivative of y=(x^2)/(1+sqrt(x)) is (4x(1+sqrt(x))-x^{3/2})/(2(1+sqrt(x))^2)
What is the first derivative of y=(x^2)/(1+sqrt(x)) ?
The first derivative of y=(x^2)/(1+sqrt(x)) is (4x(1+sqrt(x))-x^{3/2})/(2(1+sqrt(x))^2)