What is (\partial)/(\partial y)(4xln(y)) ?

The answer to (\partial)/(\partial y)(4xln(y)) is (4x)/y

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(\partial)/(\partial y)(4xln(y))

\frac{\partial}{\partial y} (4 x ln (y))

\frac{4 x}{y}

Solution steps

\frac{\partial}{\partial y} (4 x ln (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 x \frac{\partial}{\partial y} (ln (y))

Apply the common derivative:

\frac{\partial}{\partial y} (ln (y)) = \frac{1}{y}

= 4 x \frac{1}{y}

Simplify

4 x \frac{1}{y} : \frac{4 x}{y}

= \frac{4 x}{y}

f (x) = 3 x^{2} - x^{3}, (1, 2)

(- 3, - 5), (- 2, - 3)

\frac{d}{d x} ((1 + x) e^{- x})

\int 8 x^{2} d x

4 y^{^{''}} - 5 y^{^{'}} = 0, y (- 2) = 0, y^{^{'}} (- 2) = 7

What is (\partial)/(\partial y)(4xln(y)) ?
The answer to (\partial)/(\partial y)(4xln(y)) is (4x)/y