What is the derivative of (3x-2^3) ?

The derivative of (3x-2^3) is 9(3x-2)^2

What is the first derivative of (3x-2^3) ?

The first derivative of (3x-2^3) is 9(3x-2)^2

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\frac{d}{d x} ((3 x - 2)^{3})

9 (3 x - 2)^{2}

Solution steps

\frac{d}{d x} ((3 x - 2)^{3})

Apply the chain rule:

3 (3 x - 2)^{2} \frac{d}{d x} (3 x - 2)

= 3 (3 x - 2)^{2} \frac{d}{d x} (3 x - 2)

\frac{d}{d x} (3 x - 2) = 3

= 3 (3 x - 2)^{2} \cdot 3

Simplify

= 9 (3 x - 2)^{2}

y = 9 x - x^{2}, y = 2 x

\int x^{7} e^{- x^{8}} d x

y^{^{'}} + \frac{1}{x} y = x^{2} y^{1}

\int \frac{1}{3 ^{x}} d x

y^{^{'}} = 2 y + 1

What is the derivative of (3x-2^3) ?
The derivative of (3x-2^3) is 9(3x-2)^2
What is the first derivative of (3x-2^3) ?
The first derivative of (3x-2^3) is 9(3x-2)^2