What is the solution for (dh)/(dt)=-h^3 ?

The solution for (dh)/(dt)=-h^3 is h=sqrt(-1/(2(-t+c_{1)))},h=-sqrt(-1/(2(-t+c_{1)))}

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(dh)/(dt)=-h^3

\frac{d h}{d t} = - h^{3}

h = - \frac{1}{2 ( - t + c _{1} )}, h = - - \frac{1}{2 ( - t + c _{1} )}

Solution steps

\frac{d h}{d t} = - h^{3}

Solve separable ODE:

h = - \frac{1}{2 ( - t + c _{1} )}, h = - - \frac{1}{2 ( - t + c _{1} )}

h = - \frac{1}{2 ( - t + c _{1} )}, h = - - \frac{1}{2 ( - t + c _{1} )}

\frac{\partial}{\partial x} (ln (x^{2} y^{2}))

\frac{d}{d x} (e^{\frac{in x}{2 x}})

\int \frac{sin ( 2 θ )}{cos ( 2 θ )} d θ

\frac{d}{d x} (y \cdot sin (x))

x \to 2 - lim (x - 2)

What is the solution for (dh)/(dt)=-h^3 ?
The solution for (dh)/(dt)=-h^3 is h=sqrt(-1/(2(-t+c_{1)))},h=-sqrt(-1/(2(-t+c_{1)))}