What is (\partial)/(\partial x)(4(x-1)^2) ?

The answer to (\partial)/(\partial x)(4(x-1)^2) is 8(x-1)

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(\partial)/(\partial x)(4(x-1)^2)

\frac{\partial}{\partial x} (4 (x - 1)^{2})

8 (x - 1)

Solution steps

\frac{\partial}{\partial x} (4 (x - 1)^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{\partial}{\partial x} ((x - 1)^{2})

Apply the chain rule:

2 (x - 1) \frac{\partial}{\partial x} (x - 1)

= 2 (x - 1) \frac{\partial}{\partial x} (x - 1)

\frac{\partial}{\partial x} (x - 1) = 1

= 4 \cdot 2 (x - 1) \cdot 1

Simplify

= 8 (x - 1)

n = 1 \sum \infty n sin (\frac{1}{n})

\frac{\partial}{\partial x} (2 + 3 x + 4 y)

\int_{0}^{2} (4 - x^{2}) d x

\frac{2 s}{s ^{2} + 8 s + 25}

\frac{d x}{d t} - 5 x = 2 t

What is (\partial)/(\partial x)(4(x-1)^2) ?
The answer to (\partial)/(\partial x)(4(x-1)^2) is 8(x-1)