What is the solution for (dy)/(dx)+2xy=2xe^{-x^2} ?

The solution for (dy)/(dx)+2xy=2xe^{-x^2} is y=(x^2)/(e^{x^2)}+(c_{1})/(e^{x^2)}

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(dy)/(dx)+2xy=2xe^{-x^2}

\frac{d y}{d x} + 2 x y = 2 x e^{- x^{2}}

y = \frac{x ^{2}}{e ^{x^{2}}} + \frac{c _{1}}{e ^{x^{2}}}

Solution steps

\frac{d y}{d x} + 2 x y = 2 x e^{- x^{2}}

Solve linear ODE:

y = \frac{x ^{2}}{e ^{x^{2}}} + \frac{c _{1}}{e ^{x^{2}}}

y = \frac{x ^{2}}{e ^{x^{2}}} + \frac{c _{1}}{e ^{x^{2}}}

y^{^{'}} + 2 x y = 4 x

f (r) = \frac{7}{r ^{3}}

\int 3 x 5 - 2 x^{2} d x

\int cos (y^{2}) d y

\frac{e ^{- 2 s}}{s ( s + 1 )}

What is the solution for (dy)/(dx)+2xy=2xe^{-x^2} ?
The solution for (dy)/(dx)+2xy=2xe^{-x^2} is y=(x^2)/(e^{x^2)}+(c_{1})/(e^{x^2)}